Get Started
Let’s develop a small language that allows for simple computation together. Here’s a valid input file for that language:
puts(1 + 2)
puts(4 + 2)
To install the parslet library, please do a
gem install parslet
Now let’s write the first part of our parser. For now, we’ll just recognize simple numbers like ‘1’ or ‘42’.
require 'parslet'
class Mini < Parslet::Parser
rule(:integer) { match('[0-9]').repeat(1) }
root(:integer)
end
Mini.new.parse("132432") # => "132432"@0
Running this example will print “132432@0”. Congratulations! You just have
written your first parser. Running it on the input ‘puts(1)
’ will
not work yet. Let’s see what happens in case of a failure:
Mini.new.parse("puts(1)") # raises Parslet::ParseFailed
Here’s the error message provided by that exception: “Expected at least 1 of [0-9] at line 1 char 1.” parslet tries to find a number there, but can’t find one.
There are just two lines to the definition of this parser, let’s go through them:
rule(:integer) { match('[0-9]').repeat(1) }
rule
lets you create a new parser rule. Inside the block of that
:integer
rule, you find match('[0-9]').repeat(1)
.
This says: “match a character that is in the range 0-9
, then
match any number of those, but at least match one.”
root(:integer)
That second line just says: Start parsing at the rule called
:integer
.
Addition
Let’s go for simple addition. We’ll have to allow for spaces in our input, since those help make code readable.
rule(:space) { match('\s').repeat(1) }
rule(:space?) { space.maybe }
Two things are new here: (and both in the second line)
- you can use (‘call’) other rules in your rules
.maybe
, the same as.repeat(0,1)
1, indicating that the thing before it is maybe present once in the input.
Essentially, you can think about parslet rules as instructing Ruby to “parse this” and “parse that”. Calling other rules can be looked at in the same way; you tell Ruby to go off, parse that subrule and then come back with the results. This helps when thinking about rule recursion. For example, a self-recursive rule like this one will of course create an endless loop:
rule(:infinity) {
infinity >> str(';')
}
Even though infinity seems to be delimited by ‘;’, in reality, infinity is
very long, especially towards the end. There is no way of knowing for the
parser when to stop processing infinity
and start reading
semicolons. Ergo, we need to make sure we talk about concrete items that
consume input first, and then do recursion. This way we ensure that our
grammar terminates, since in a way, it is like a normal program.
Here’s the full parser:
class Mini < Parslet::Parser
rule(:integer) { match('[0-9]').repeat(1) >> space? }
rule(:space) { match('\s').repeat(1) }
rule(:space?) { space.maybe }
rule(:operator) { match('[+]') >> space? }
rule(:sum) { integer >> operator >> expression }
rule(:expression) { sum | integer }
root :expression
end
def parse(str)
mini = Mini.new
mini.parse(str)
rescue Parslet::ParseFailed => failure
puts failure.parse_failure_cause.ascii_tree
end
parse "1 + 2 + 3" # => "1 + 2 + 3"@0
parse "a + 2" # fails, see below
As you can see, the parser got decorated with the space?
idiom.
Every atom of our language consumes the space right after it. This is a useful
convention that makes top level rules (the important ones) look cleaner.
Note also the addition of :operator
, :sum
and
:expression
. The runner code has been extended a bit, so as to
throw nice explanations of what went wrong when a parse failure is
encountered. Running the code on ‘a + 2
’ for example outputs:
Expected one of [SUM, INTEGER] at line 1 char 1. |- Failed to match sequence (INTEGER OPERATOR EXPRESSION) at line 1 char 1. | `- Failed to match sequence ([0-9]{1, } SPACE?) at line 1 char 1. | `- Expected at least 1 of [0-9] at line 1 char 1. | `- Failed to match [0-9] at line 1 char 1. `- Failed to match sequence ([0-9]{1, } SPACE?) at line 1 char 1. `- Expected at least 1 of [0-9] at line 1 char 1. `- Failed to match [0-9] at line 1 char 1.
This is what parslet calls an #error_tree
. Not only the output of
your parser, but also its grammar is constructed like a tree. When things go
wrong, every branch of the tree has its own reasons for not accepting a given
input. The #parse_failure_cause
method returns those reasons.
Our grammar has essentially two branches, SUM
and
INTEGER
. Can you see why all rules expect a number as the first
character?
Tree output (and what to do about it)
But if we leave the negative examples for a second; what happens if the parse succeeds? It turns out, not much:
parse "1 + 2 + 3" # => "1 + 2 + 3"@0
The only notable difference between input and output is that the output has an
extra ‘@0’ appended to it. This is related to line number tracking and will be
explained later on (or you can skip ahead and look up
Parslet::Slice
).
The code we now have parses the input successfully, but doesn’t do much else. Parslet hasn’t got its own opinion on what to do with your input. By default, it will just play it back to you. But parslet provides also a method of structuring its output:
# Without structure: just strings.
str('ooo').parse('ooo') # => "ooo"@0
str('o').repeat.parse('ooo') # => "ooo"@0
# Added structure: .as(...)
str('ooo').as(:ex1).parse('ooo') # => {:ex1=>"ooo"@0}
long = str('o').as(:ex2a).repeat.as(:ex2b).parse('ooo')
long # => {:ex2b=>[{:ex2a=>"o"@0}, {:ex2a=>"o"@1}, {:ex2a=>"o"@2}]}
You get to name things the way you want! This is also free. Seriously: parslet
requires you to add all the structure to its output. Annotate important parts
of your grammar with .as(:symbol)
and get back a tree-like
structure composed of hashes (sequence), arrays (repetition) and strings (like
we had initially).
Once you start naming things, you’ll notice that what you don’t name, disappears. Parslet assumes that what you don’t name is unimportant.
parser = str('a').as(:a) >> str(' ').maybe >>
str('+').as(:o) >> str(' ').maybe >>
str('b').as(:b)
parser.parse('a + b') # => {:a=>"a"@0, :o=>"+"@2, :b=>"b"@4}
Think of this like using a highlighter on your input: What is there not to like about neon yellow?
Making the parser complete
Let’s look at the complete parser definition that also allows for function calls:
class MiniP < Parslet::Parser
# Single character rules
rule(:lparen) { str('(') >> space? }
rule(:rparen) { str(')') >> space? }
rule(:comma) { str(',') >> space? }
rule(:space) { match('\s').repeat(1) }
rule(:space?) { space.maybe }
# Things
rule(:integer) { match('[0-9]').repeat(1).as(:int) >> space? }
rule(:identifier) { match['a-z'].repeat(1) }
rule(:operator) { match('[+]') >> space? }
# Grammar parts
rule(:sum) { integer.as(:left) >> operator.as(:op) >> expression.as(:right) }
rule(:arglist) { expression >> (comma >> expression).repeat }
rule(:funcall) { identifier.as(:funcall) >> lparen >> arglist.as(:arglist) >> rparen }
rule(:expression) { funcall | sum | integer }
root :expression
end
require 'pp'
pp MiniP.new.parse("puts(1 + 2 + 3, 45)")
That’s really all there is to it — our language is a really simple language.
When fed with a string like ’puts(1 + 2 + 3, 45)
, our parser outputs
the following:
{:funcall=>"puts"@0, :arglist=> [{:left=>{:int=>"1"@5}, :op=>"+ "@7, :right=>{:left=>{:int=>"2"@9}, :op=>"+ "@11, :right=>{:int=>"3"@13}}}, {:int=>"45"@16}]}
Parslet calls this the intermediary tree. There are three types of nodes in this tree:
- Hashes: a node that has named subtrees
- Arrays: a node storing a collection of sub-nodes
- Strings are the leaves, containing the accepted source
The format of this tree is easy to work with and to read. Here’s what the above tree would look like as a graphic:
Where to go from here: An Interpreter
As nice as the format above is for printing and looking at – it may be difficult at times to get the information out of it again. Let’s look at how to transform the tree:
class SimpleTransform < Parslet::Transform
rule(funcall: 'puts', arglist: sequence(:args)) {
"puts(#{args.inspect})"
}
# ... other rules
end
tree = {funcall: 'puts', arglist: [1,2,3]}
SimpleTransform.new.apply(tree) # => "puts([1, 2, 3])"
Transformation is an entire topic by itself; this will be covered in detail later on. To whet your appetite, let me just give you a few teasers:
- Transformations match portions of your tree at any depth, replacing them with whatever you decide.
- In addition to
sequence(sym)
, there is alsosimple(sym)
andsubtree(sym)
. Those match simple strings and entire subtrees respectively. Caution with the latter.
Here’s how you would write a somewhat classical interpreter for our little language by using a transformation. Note that from this point on, there is not one way to go about this, but thousands; you are really free (and on your own):
class MiniP < Parslet::Parser
# Single character rules
rule(:lparen) { str('(') >> space? }
rule(:rparen) { str(')') >> space? }
rule(:comma) { str(',') >> space? }
rule(:space) { match('\s').repeat(1) }
rule(:space?) { space.maybe }
# Things
rule(:integer) { match('[0-9]').repeat(1).as(:int) >> space? }
rule(:identifier) { match['a-z'].repeat(1) }
rule(:operator) { match('[+]') >> space? }
# Grammar parts
rule(:sum) {
integer.as(:left) >> operator.as(:op) >> expression.as(:right) }
rule(:arglist) { expression >> (comma >> expression).repeat }
rule(:funcall) {
identifier.as(:funcall) >> lparen >> arglist.as(:arglist) >> rparen }
rule(:expression) { funcall | sum | integer }
root :expression
end
IntLit = Struct.new(:int) do
def eval; int.to_i; end
end
Addition = Struct.new(:left, :right) do
def eval; left.eval + right.eval; end
end
FunCall = Struct.new(:name, :args) do
def eval; p args.map { |s| s.eval }; end
end
class MiniT < Parslet::Transform
rule(:int => simple(:int)) { IntLit.new(int) }
rule(
:left => simple(:left),
:right => simple(:right),
:op => '+') { Addition.new(left, right) }
rule(
:funcall => 'puts',
:arglist => subtree(:arglist)) { FunCall.new('puts', arglist) }
end
parser = MiniP.new
transf = MiniT.new
ast = transf.apply(
parser.parse(
'puts(1,2,3, 4+5)'))
ast.eval # => [1, 2, 3, 9]
That’s a bunch of code for printing [1, 2, 3, 9]
. Welcome to the
fantastic world of compiler and interpreter writing!
1 As far as parsing goes. There is a subtle difference between
#repeat(0,1)
and #maybe
. Can you figure it out?